Cod: Selectaţi tot
mysql_connect ( $dbhost, $dbuser, $dbpass) or die("Could not connect: ".mysql_error());
mysql_select_db($dbname) or die(mysql_error());
$username=$_COOKIE["useru"];
$qtitle=$_POST["title"];
$content=$_POST["textu"];
$data=date("Y/m/d");
$uid="SELECT userid FROM users WHERE username='$username'";
$result=mysql_query($uid);
$query = "INSERT INTO questions (user, title, content, userid, date)
VALUES('$username', '$qtitle', '$content', '$result', '$data')";
mysql_query($query) or die(mysql_error());
mysql_close();
?>Sunt tabelele users si questions. Vreau sa selecteze din tabelul users, ID-ul userului logat si sa il introduca il questions. In tabelul questions, la coloana userid primesc insa asta: Resource id #2
Sper ca m-ati inteles, ms.[/b]
