[php]base64_decode($pass)
$cerereSql=mysql_query("SELECT * FROM user_pass WHERE user='".$user."' AND pass='".$pass."'",$connect) or die ("nu pot cauta ");[/php]
asta e secventa de cot care cauta in baza de date userul si passu si
am un echo mai incolo care imi afiseaza rezultatu dar faza e ca imi zice
base64_decode() nedd 1 to be a string
asa si mai am inca o problema
am incercat fara base64 ... parola si userul au fost necriptate ... sunt bagate in baza de date sub forma user: gigi pass: vasile
acum am facut loginu care arata cam asa
[php]
<?php
include("config.php");
$cerereSql=mysql_query("SELECT * FROM user_pass WHERE user='".$user."' AND pass='".$pass."'",$connect) or die ("nu pot cauta ");
$rezultat=mysql_query($cerereSql);
$numrw=mysql_num_rows($rezultat);
if($numrw){
$getid = "SELECT * FROM user_pass WHERE user='".$user."' LIMIT 1";
$getidexec =mysql_query($getid);
while($r=mysql_fetch_array($getidexec)){
$userid = $r[userid];
}
setcookie( "userid", "$userid", time()+3600, "/", "", 0 );
echo "User Logged in.<br><br><a href=\"index.php\">Continue...</a>";
}
else {
echo ("nici o incercare");
}
?>[/php]
asa si primesc urmatoarea eroare :Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource
care e faza am incercat si cu @ in fata comenzii mysql_num_rows si se duce pa ramura de else adia primesc mesajul "nici o incercare"

( numai eroari