Forum PHP Romania - Discutii despre PHP, MySQL, Javascript, AJAX, etc

[dinamics]

Buna am in flash urmatorul fragment de cod: this.sendData = function ()
{
this.date = new Date();
var _loc3 = this.date.getDate() + "." + (this.date.getMonth() + 1) + "." + this.date.getFullYear();
var _loc2 = "guestbook.php?name=" + this.nameTxt_mc.txt.text + "&mail=" + this.mailTxt_mc.txt.text + "&message=" + this.messageTxt_mc.txt.text + "&date=" + _loc3;
loadVariables(_loc2, this);
this.sendBtn.buTitle.txtF.text = "";
this.sendBtn.buTitle.txtF.aniTextReverse(this.datObj.duringSend.toUpperCase(), 2);
this.nameTxt_mc.txt.aniTextOut(2, 2);
this.mailTxt_mc.txt.aniTextOut(2, 2);
this.messageTxt_mc.txt.aniTextOut(6, 2, this.unbuild, this);
this.onEnterFrame = function ()
{
if (this.eof == "TRUE")
{
this.gotoAndPlay("sending");
this._parent._parent.accessXML(this._parent._parent.xmlLink + ".xml");
delete this.onEnterFrame;
} // end if
};
};


Dupa introducerea variabilelor in formular am eroare:

Error opening URL "file:///C|/...../EasyPHP1%2D8/www/guestbook.php?name=variabila1&mail=variabila2&message=variabila3&date=26.6.2006"


iar fisierul guestbook.php arata asa

<?php
header("Content-type: text/xml");
$host = "localhost";
$user = "root";
$pass = "";
$database = "guestbook";
$linkID = mysql_connect($host, $user, $pass) or die("Could not connect to host.");
mysql_select_db($database) or die("Could not find database.");
$name="$name";
$date="$date";
$mail="$mail";
$message="$message";
$cerereSQL="INSERT INTO formular (name,date,website,text)
VALUES ('$name','$date','$mail','$message')";
mysql_query($cerereSQL);
require_once('guestbook1.php');
?>

Nu stiu unde gresesc dar nu merge, nu transmite datele.
Poate cineva sa ma lamureasca?

[johnutz]

:lol:
esti sigur ca ai accesat guestbook-ul prin http://localhost/ ?
:lol:

[dinamics]

Da, adica daca deschid numai guestbook.php din browser functioneaza dar nu recunoaste variabilele
Notice: Undefined variable: name in c:\program files\easyphp1-8\www\guestbook.php on line 8

[Pirahna]

ma intreb de ce

$name="$name";

[PHPRomania Bot]