Forum PHP Romania - Discutii despre PHP, MySQL, Javascript, AJAX, etc

moonlord · Data înscrierii: 15/Iul/2007 Mesaje: 95

de ce nu afiseaza noul select?

meniu.php :
Cod:
<HTML>
<HEAD>
<TITLE>TEST</TITLE
<script language="javascript">
function getXMLHTTPRequest() {
try {
req = new XMLHttpRequest();
} catch(err1) {
try {
req = new ActiveXObject("Msxml2.XMLHTTP");
} catch (err2) {
try {
req = new ActiveXObject("Microsoft.XMLHTTP");
} catch (err3) {
req = false;
}
}
}
return req;
}
var http = getXMLHTTPRequest();
function loadCities() {
var id=document.getElementById('countries').value;
var url="meniudb.php?id"+id;
http.open("GET",url,true);
http.onreadystatechange = useHttpResponse;
http.send(null);
}
function useHttpResponse() {
if (http.readyState == 4) {
if(http.status == 200) {
var timeValue = http.responseText;
document.getElementById('result').innerHTML = timeValue;
}
} else {
document.getElementById('result').innerHTML = '<img src="loader.gif" />';
}
}
</script>
</HEAD>
<BODY>
<select id="countries" onchange="loadCities()">
<option value="1">Romania</option>
<option value="2">USA</option>
<option value="3">England</option>
</select>
<div id="result"></div>
</BODY
</HTML>

meniudb.php:

Cod:
<?php
require_once('connections.php');
$id=$_GET['id'];
$sql="SELECT * FROM categorii,subcategorii WHERE IDcategorie='$id'";
$result=mysql_query($sql) or die(mysql_error());
while ($row=mysql_fetch_array($result)) {
echo "<SELECT>";
echo "<OPTION>{$row['Numesubcategorie']}</OPTION>";
echo "</SELECT>";
}
?>

dechim · Trimis: Mie Oct 17, 2007 10:30 pm Titlul subiectului:

In function loadCities() linia
Cod:
var url="meniudb.php?id"+id;

trebuie
Cod:
var url="meniudb.php?id="+id;

:D

PHPRomania Bot · Mie Dec 26, 2007 7:01 pm